Question

1. a =? l × w

a = __×__ put 14 in place of l and 5 in place of w.
a = ____ multiply.
the area is ____ square inches.

1. find the temperature in °f when it is 20°c.

use the formula f = 1.8c + 32.
f = 1.8c + 32
f = 1.8×____+ 32 put 20 in place of c.
f = ____+ 32 use order of operations. multiply first.
f = ____ add.
the temperature is ____°f.

1. reasoning use your answer to 4 above to explain if a temperature of 30°c is warmer or colder than 68°f.

Explanation:

Step1: Solve problem 3

Calculate area

Given the formula for the area of a rectangle $A = l\times w$. Substitute $l = 14$ and $w = 5$ into the formula.
$A=14\times5$
$A = 70$
The area is 70 square inches.

Step2: Solve problem 4

Convert temperature

Given the formula $F=1.8C + 32$. Substitute $C = 20$ into the formula.
$F=1.8\times20+32$
First, multiply: $1.8\times20 = 36$.
$F=36 + 32$
Then, add: $F = 68$
The temperature is 68°F.

Step3: Solve problem 5

Compare temperatures

We know from problem 4 that $20^{\circ}C$ is $68^{\circ}F$.
Use the formula $F=1.8C + 32$ to find the Fahrenheit - equivalent of $30^{\circ}C$.
$F=1.8\times30+32$
$F = 54+32$
$F=86$
Since $86^{\circ}F>68^{\circ}F$, a temperature of $30^{\circ}C$ is warmer than $68^{\circ}F$.

Answer:

1. $A = 14\times5$, $A = 70$, 70
2. $F=1.8\times20 + 32$, $F = 36+32$, $F = 68$, 68
3. A temperature of $30^{\circ}C$ is warmer than $68^{\circ}F$ because when $C = 30$, $F=1.8\times30+32=86^{\circ}F$ and $86^{\circ}F>68^{\circ}F$.