QUESTION IMAGE
Question
- the quadratic expression ( x^2 - 8x + 10 ) has its smallest value for some integer value of ( x ) on the interval ( 0 leq x leq 10 ). set up a table to find the smallest value of the expression and the value of ( x ) that gives this value. show your table below.
- consider the complex expression ( (x + 7)(x + 3) + (x - 1)(x - 4) ).
(a) multiply the two sets of binomials and combine like terms in order to write this expression as an equivalent trinomial in standard form. show your work.
(b) set up a table to verify that your answer in part (a) is equivalent to the original expression. dont hesitate to point out that it is not equivalent (which means you either made a mistake in your algebra or in your table set up). show your table.
- the product of three binomials is shown below. write this product as a polynomial in standard form. (its highest power will be ( x^3 )).
( (x - 1)(x + 2)(x - 4) )
- set up a table for the answer you found in #6 on the interval ( -5 leq x leq 5 ). where does this expression have zeroes?
Problem 4
Step1: Create table for integer x
| $x$ | $x^2 - 8x + 10$ |
|---|---|
| 1 | $1^2 -8(1)+10=3$ |
| 2 | $2^2 -8(2)+10=-2$ |
| 3 | $3^2 -8(3)+10=-5$ |
| 4 | $4^2 -8(4)+10=-6$ |
| 5 | $5^2 -8(5)+10=-5$ |
| 6 | $6^2 -8(6)+10=-2$ |
| 7 | $7^2 -8(7)+10=3$ |
| 8 | $8^2 -8(8)+10=10$ |
| 9 | $9^2 -8(9)+10=19$ |
| 10 | $10^2 -8(10)+10=30$ |
Step2: Identify minimum value
Scan the calculated values to find the smallest.
Step1: Multiply first binomial pair
$(x+7)(x+3) = x^2 +3x +7x +21 = x^2 +10x +21$
Step2: Multiply second binomial pair
$(x-1)(x-4) = x^2 -4x -x +4 = x^2 -5x +4$
Step3: Add and combine like terms
$(x^2 +10x +21) + (x^2 -5x +4) = 2x^2 +5x +25$
Step1: Choose test x values
Pick integer values for $x$ to test both expressions.
Step2: Build verification table
| $x$ | Original Expression $(x+7)(x+3)+(x-1)(x-4)$ | Simplified Expression $2x^2+5x+25$ |
|---|---|---|
| -1 | $(6)(2)+(-2)(-5)=12+10=22$ | $2(1)+5(-1)+25=2-5+25=22$ |
| 0 | $(7)(3)+(-1)(-4)=21+4=25$ | $2(0)+5(0)+25=25$ |
| 1 | $(8)(4)+(0)(-3)=32+0=32$ | $2(1)+5(1)+25=2+5+25=32$ |
| 2 | $(9)(5)+(1)(-2)=45-2=43$ | $2(4)+5(2)+25=8+10+25=43$ |
Step3: Confirm equivalence
All test values produce matching results, so the expressions are equivalent.
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The smallest value is $-6$, which occurs when $x=4$.
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