Question

question 10 (1 point) when keeping the mass of the sledder the same, as the height of the hill increased, the speed word bank: decreased stayed the same increased blank 1:

Explanation:

Step1: Apply conservation of energy

The initial potential energy of the sledder at the top of the hill is $U = mgh$ (where $m$ is mass, $g$ is gravitational - acceleration, $h$ is height). At the bottom of the hill, assuming no friction, this potential energy is converted into kinetic energy $K=\frac{1}{2}mv^{2}$. So, $mgh=\frac{1}{2}mv^{2}$.

Step2: Solve for velocity

Canceling out the mass $m$ from both sides of the equation $mgh=\frac{1}{2}mv^{2}$, we get $v = \sqrt{2gh}$. As $h$ (height of the hill) increases, and $g$ is a constant, the value of $v$ (speed) increases.

Answer:

increased