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Question
question 10 (5 points)
how many molecules of o2 will be required to react completely with 0.600 mol of h2 in order to form water?
a) 0.300 molecules
b) 7.23 1023 molecules
c) 1.81 1023 molecules
d) 3.61 1023 molecules
Step1: Write the balanced equation
The reaction between \(H_2\) and \(O_2\) to form \(H_2O\) is \(2H_2 + O_2
ightarrow 2H_2O\). From the equation, 2 moles of \(H_2\) react with 1 mole of \(O_2\).
Step2: Find moles of \(O_2\)
Given moles of \(H_2 = 0.600\) mol. Using the mole ratio (\(\frac{1\ mol\ O_2}{2\ mol\ H_2}\)), moles of \(O_2=\frac{0.600}{2}= 0.300\) mol.
Step3: Calculate number of molecules
Using Avogadro's number (\(N_A = 6.022\times10^{23}\) molecules/mol), number of \(O_2\) molecules \(= 0.300\ mol\times6.022\times10^{23}\) molecules/mol \(= 1.8066\times10^{23}\approx1.81\times10^{23}\) molecules.
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c) \(1.81\times10^{23}\) molecules