Question

question 10
1 pts
according to the laws of thermal radiation, hotter objects emit photons with
lower average energy
higher average masses
higher average speeds
lower average frequencies
shorter average wavelengths

Explanation:

According to Wien's displacement law and the relationship between photon energy, frequency, and wavelength ($E = h
u=\frac{hc}{\lambda}$, where $E$ is energy, $h$ is Planck's constant, $
u$ is frequency, $c$ is the speed of light, and $\lambda$ is wavelength), hotter objects emit radiation with a higher - frequency (shorter - wavelength) peak. Photons have no mass and all photons travel at the speed of light in a vacuum. Higher - temperature objects emit photons with higher average energy.

Answer:

E. shorter average wavelengths