Question

question 11
in may you used 1300 kilowatt - hours of energy for electricity. calculate your average power use in watts. (round your answer to the nearest whole number)
2.5 pts
question 10
the advisory speed limit of the german autobahn is 81 miles per hour. convert this to kilometers per hour. (use 1 mi = 1.6093 km) (round to two decimal places)
2.5 pts
the population of the united states in 2000 was roughly 280 million. express this as the number of people per square mile. the land area of the united states is roughly 3.536,000 square miles.
o 790 people/mi²
o 79 people/mi²
o 79 mi²/people
o 8 people/mi²

Explanation:

Step 1: Solve Question 10 - Speed conversion

We know that 1 mile = 1.6093 km. To convert 81 miles per hour to kilometers per hour, we multiply 81 by 1.6093.
$81\times1.6093 = 130.3533$ km/h. Rounding to two - decimal places, we get 130.35 km/h.

Step 2: Solve Question 11 - Power calculation

There are 31 days in May. The total number of hours in May is $31\times24=744$ hours.
The total energy used is 1300 kilowatt - hours. To find the average power use in watts, first convert kilowatt - hours to watt - hours. 1300 kilowatt - hours is $1300\times1000 = 1300000$ watt - hours.
The average power $P=\frac{1300000}{744}\approx1747$ watts. Rounding to the nearest whole number, we get 1747 watts.

Answer:

Question 10: 130.35
Question 11: 1747