Question

question 12 0/2 pts 3 9 details ages number of students 15-18 9 19-22 10 23-26 8 27-30 5 31-34 10 35-38 9 based on the frequency distribution above, find the relative frequency for the class with lower class limit 15 relative frequency = % give your answer as a percent, rounded to one decimal place question help: video

Explanation:

Step1: Calculate total number of students

$9 + 10+8 + 5+10+9=51$

Step2: Calculate relative frequency for the class 15 - 18

The frequency of the class with lower - class limit 15 (i.e., 15 - 18) is 9. The relative frequency formula is $\text{Relative Frequency}=\frac{\text{Frequency of the class}}{\text{Total frequency}}\times100\%$. So, $\text{Relative Frequency}=\frac{9}{51}\times100\%$.
$\frac{9}{51}\times100\%=\frac{900}{51}\% \approx 17.6\%$

Answer:

$17.6\%$