Question

question 13 of 25
a train accelerates at -1.5 m/s² for 10 seconds. if the train had an initial speed of 32 m/s, what is its new speed?
a. 17 m/s
b. 32 m/s
c. 15 m/s
d. 47 m/s

Explanation:

Step1: Identify the relevant formula

The formula for final - velocity is $v = v_0+at$, where $v$ is the final velocity, $v_0$ is the initial velocity, $a$ is the acceleration and $t$ is the time.

Step2: Substitute the given values

We are given that $v_0 = 32\ m/s$, $a=- 1.5\ m/s^{2}$, and $t = 10\ s$. Substitute these values into the formula: $v=32+( - 1.5)\times10$.

Step3: Calculate the result

First, calculate $(-1.5)\times10=-15$. Then, $v = 32-15$. So, $v = 17\ m/s$.

Answer:

A. 17 m/s