Question

question 22 of 30
what is the reactant(s) in the chemical equation below?
2al(s) + 2naoh(aq) + 2h2o(l) → 2naalo2(aq) + 3h2(g)
a. 2al(s)
b. 3h2(g)
c. 2al(s) + 2naoh(aq) + 2h2o(l)
d. 2naalo2(aq) + 3h2(g)

Explanation:

In a chemical equation, reactants are on the left - hand side of the arrow. Here, the substances on the left - hand side are aluminum (Al), sodium hydroxide (NaOH), and water ($H_2O$).

Answer:

C. $2Al(s)+2NaOH(aq)+2H_2O(l)$