Question

question 3 of 22 determine the quantity of molecules in 2.00 moles of p₄ (with a setup including starting amount, a conversion factor box, and options: 1.20×10²⁴, 2, 123.90, 1, 6.022×10²³, 2.41×10²⁴, 4.82×10²⁴, 4, 2.00, 30.97, mol p₄, g/mol p₄, g p₄, molecules p₄)

Explanation:

Step1: Identify starting amount

The starting amount is 2.00 moles of \( P_4 \), so we write \( 2.00 \, \text{mol } P_4 \).

Step2: Use Avogadro's number conversion factor

Avogadro's number is \( 6.022 \times 10^{23} \) molecules per mole. The conversion factor is \( \frac{6.022 \times 10^{23} \, \text{molecules } P_4}{1 \, \text{mol } P_4} \).

Step3: Multiply starting amount by conversion factor

\[
2.00 \, \text{mol } P_4 \times \frac{6.022 \times 10^{23} \, \text{molecules } P_4}{1 \, \text{mol } P_4} = 1.2044 \times 10^{24} \, \text{molecules } P_4 \approx 1.20 \times 10^{24} \, \text{molecules } P_4
\]

Answer:

The quantity of molecules in 2.00 moles of \( P_4 \) is \( \boldsymbol{1.20 \times 10^{24}} \) molecules (or approximately \( 1.20 \times 10^{24} \) when using the given options, the calculation gives \( 2.00 \times 6.022 \times 10^{23}=1.2044\times 10^{24}\approx 1.20\times 10^{24} \)). The filled - in format would be: Starting amount: \( 2.00 \, \text{mol } P_4 \), conversion factor numerator: \( 6.022 \times 10^{23} \, \text{molecules } P_4 \), conversion factor denominator: \( 1 \, \text{mol } P_4 \), and the answer is \( 1.20 \times 10^{24} \, \text{molecules } P_4 \).