Question

question 28
if an objects temperature is 12,350 k, what is its peak wavelength?
0.002348 nm
234.8 nm
3.58 x 10^10 nm
12350 nm
2.76x10^10nm

Explanation:

Step1: Recall Wien's displacement law

$\lambda_{max}T = b$, where $b = 2.898\times10^{6}\ nm\cdot K$ and $T$ is the temperature in Kelvin, $\lambda_{max}$ is the peak - wavelength.

Step2: Solve for $\lambda_{max}$

$\lambda_{max}=\frac{b}{T}$. Given $T = 12350\ K$, then $\lambda_{max}=\frac{2.898\times10^{6}\ nm\cdot K}{12350\ K}$.

Step3: Calculate the value

$\lambda_{max}=\frac{2.898\times10^{6}}{12350}\ nm\approx234.8\ nm$.

Answer:

234.8 nm