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question: 32 of 38 a bag contains five green balls, four red balls, and…

Question

question: 32 of 38
a bag contains five green balls, four red balls, and three yellow balls. if one ball is randomly sel probability that the ball is red?
5/12
1/4
1/2
1/3

Explanation:

Step1: Calculate total number of balls

We sum the number of green, red, and yellow balls. The number of green balls is 5, red is 4, and yellow is 3. So total number of balls \( n = 5 + 4 + 3 = 12 \).

Step2: Calculate probability of red ball

The probability of an event is the number of favorable outcomes (red balls) divided by the total number of outcomes (total balls). The number of red balls \( r = 4 \), total balls \( n = 12 \). So probability \( P(\text{red})=\frac{4}{12}=\frac{1}{3} \).

Answer:

\(\frac{1}{3}\) (corresponding to the option with \( 1/3 \))