Question

question 4 of 37
identify the conjugate acid for each base.
conjugate acid of hs⁻:
conjugate acid of po₄³⁻:
conjugate acid of nh₃:

Explanation:

Step1: Add H⁺ to HS⁻

A base gains 1 H⁺ to form its conjugate acid.
$\text{HS}^- + \text{H}^+
ightarrow \text{H}_2\text{S}$

Step2: Add H⁺ to PO₄³⁻

A base gains 1 H⁺ to form its conjugate acid.
$\text{PO}_4^{3-} + \text{H}^+
ightarrow \text{HPO}_4^{2-}$

Step3: Add H⁺ to NH₃

A base gains 1 H⁺ to form its conjugate acid.
$\text{NH}_3 + \text{H}^+
ightarrow \text{NH}_4^+$

Answer:

conjugate acid of HS⁻: $\text{H}_2\text{S}$
conjugate acid of PO₄³⁻: $\text{HPO}_4^{2-}$
conjugate acid of NH₃: $\text{NH}_4^+$