Question

question 45 1 point what is i printed in the following code? public class test { public static void main(string args) { int j = 0; int i = j++ + j * 5; system.out.println(\what is i? \ + i); } } a 5 b 6 c 0 d 1

Explanation:

Step1: Analyze post - increment operator

The post - increment operator j++ first uses the current value of j in the expression and then increments j by 1. Initially, j = 0. In the expression i = j++ + j * 5, when we evaluate j++, we use the value of j as 0, and then j is incremented to 1.

Step2: Evaluate the expression

After the j++ part, j becomes 1. Now we evaluate the second part j 5 with j = 1, so j 5=1 * 5 = 5. The first part j++ (the value used) is 0. Then we add these two results: 0+5 = 5. So i = 5.

Answer:

A. 5