Question

question 5
the density of silver is 10.5 g/cm³. a piece of silver with a mass of 101 g would occupy a volume of ______ cm³.
6.44
0.171
0.00155
10.5
9.62
1 pts
question 6
what happens to the mass number and the atomic number of an element when it undergoes beta (-) decay?
the mass number decreases by 4 and the atomic number decreases by 2.
neither the mass number nor the atomic number changes.
the mass number does not change and the atomic number decreases by 2.
the mass number increases by 2 and the atomic number increases by 1.
the mass number does not change and the atomic number increases by 1.

Explanation:

Question 5

Step1: Recall density formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume. We need to solve for $V$, so $V = \frac{m}{
ho}$.

Step2: Substitute values

Given $m = 101\ g$ and $
ho=10.5\ g/cm^{3}$. Then $V=\frac{101}{10.5}\ cm^{3}\approx9.62\ cm^{3}$.

In beta - (-) decay, a neutron in the nucleus changes into a proton, an electron and an antineutrino. The electron is emitted as a beta - particle. Since a neutron turns into a proton, the atomic number (number of protons) increases by 1. The mass number (sum of protons and neutrons) remains the same because the total number of nucleons does not change.

Answer:

9.62

Question 6