Question

question 2 (2 points)
how many grams of nacl (mm = 58.44 g/mol) are required to prepare 0.250 l of a 5.70 m solution?
14.6 g
175 g
58.4 g
83.3 g
43.8 g

Explanation:

Step1: Calculate moles of NaCl

Use the formula $n = M\times V$, where $M$ is molarity and $V$ is volume.
$n=5.70\ mol/L\times0.250\ L = 1.425\ mol$

Step2: Calculate mass of NaCl

Use the formula $m=n\times MM$, where $n$ is moles and $MM$ is molar - mass.
$m = 1.425\ mol\times58.44\ g/mol=83.3\ g$

Answer:

$83.3\ g$