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Question
this quiz may take you two times, and you have (at most) 1 hour to complete it once opened. your score will be the highest of your two attempts. do not start the quiz unless you have sufficient time to work on it without any distractions. you will need to have scratch paper, a pencil, a non - graphing calculator, and a clean copy of the normal table to work through these problems. do not hit submit unless you have answered all 10 questions. note: the quizzes make use of the standard normal table which has been provided within the content sections and posted in the tables module. it does not use the more exact values which may be obtained from an internet calculator. please use the table to obtain z - values as you take your quizzes and tests in this course. this quiz is due on sunday before midnight. question 1 1 pts if \\(\mu = 21\\) and \\(\sigma = 8\\), find the z - score for an observation of 27. \\(\circ - 0.481\\) \\(\circ 0.905\\) \\(\circ 0.481\\) \\(\circ - 0.905\\) \\(\circ - 0.75\\) \\(\circ 0.75\\) question 2 1 pts use your normal table to find \\(p(-0.67 < z \leq - 0.09)\\). \\(\circ.7873\\) \\(\circ.2810\\) \\(\circ.7155\\) \\(\circ.2127\\) \\(\circ.2845\\) \\(\circ.7190\\) question 3 1 pts
Question 1
Step1: Recall z - score formula
The formula for the z - score is $z=\frac{x-\mu}{\sigma}$, where $x$ is the observation, $\mu$ is the mean, and $\sigma$ is the standard deviation.
Step2: Substitute values
We are given that $\mu = 21$, $\sigma=8$, and $x = 27$. Substitute these values into the formula: $z=\frac{27 - 21}{8}=\frac{6}{8}=0.75$.
Step1: Recall normal table usage
To find $P(- 0.67 Using the standard normal table, for $z=-0.09$, the cumulative probability $P(z\leq - 0.09)=0.4641$. Using the standard normal table, for $z = - 0.67$, the cumulative probability $P(z\leq - 0.67)=0.2514$. Subtract the two probabilities: $0.4641-0.2514 = 0.2127$.Step2: Find $P(z\leq - 0.09)$
Step3: Find $P(z\leq - 0.67)$
Step4: Calculate the difference
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