Question

the reaction below produces a solid that some ct scans use as a marker.
bacl₂ + na₂so₄ →
what is the molar mass of the solid product?
? (g/mol)

Explanation:

Step1: Identify the solid product

The reaction is a double - displacement reaction. The general form of a double - displacement reaction is \(AB + CD
ightarrow AD+CB\). For the reaction \(BaCl_{2}+Na_{2}SO_{4}
ightarrow\), the products are \(BaSO_{4}\) (solid) and \(NaCl\) (aqueous). So the solid product is \(BaSO_{4}\).

Step2: Calculate the molar mass of \(BaSO_{4}\)

The molar mass of a compound is the sum of the molar masses of its constituent atoms.

• The molar mass of \(Ba\) (barium) is \(137.33\space g/mol\).
• The molar mass of \(S\) (sulfur) is \(32.07\space g/mol\).
• The molar mass of \(O\) (oxygen) is \(16.00\space g/mol\), and there are 4 oxygen atoms in \(BaSO_{4}\).

The molar mass of \(BaSO_{4}\), \(M = M_{Ba}+M_{S}+4\times M_{O}\)

Substitute the values:
\(M=137.33 + 32.07+4\times16.00\)
\(=137.33 + 32.07+64.00\)
First, add \(137.33\) and \(32.07\): \(137.33 + 32.07=169.4\)
Then add \(64.00\) to \(169.4\): \(169.4+64.00 = 233.4\space g/mol\)

Answer:

\(233.4\)