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remember... ionic bond covalent bond between a metal and non - metal (m…

Question

remember... ionic bond covalent bond between a metal and non - metal (m + nm) between a non - metal and non - metal (nm + nm) part 1: determine if the elements in the following compounds are metals or non - metals. describe the type of bonding that occurs in the compound. compound element 1 (metal or non - metal?) element 2 (metal or non - metal?) bond type no2 n = non - metal o = non - metal covalent nacl so2 p4 mgbr2 cao h2o k2o alf3 o2 o = nm o = nm covalent cucl2 no2 co2 hf rb2s rb = metal s = nm ionic nbr3 fe2o3 ccl4 c = nm cl = nm covalent

Explanation:

Step1: Recall metal - non - metal classification

Metals are typically found on the left - hand side and middle of the periodic table, non - metals on the right.

Step2: Recall bonding rules

Ionic bonds form between a metal and a non - metal, covalent bonds form between non - metals.

Step3: Analyze NaCl

Na (sodium) is a metal, Cl (chlorine) is a non - metal. So, the bond type is ionic.

Step4: Analyze SO₂

S (sulfur) is a non - metal, O (oxygen) is a non - metal. So, the bond type is covalent.

Step5: Analyze P₆

P (phosphorus) is a non - metal. Since it's a non - metal compound, the bond within it is covalent.

Step6: Analyze MgBr₂

Mg (magnesium) is a metal, Br (bromine) is a non - metal. So, the bond type is ionic.

Step7: Analyze CaO

Ca (calcium) is a metal, O (oxygen) is a non - metal. So, the bond type is ionic.

Step8: Analyze H₂O

H (hydrogen) is a non - metal, O (oxygen) is a non - metal. So, the bond type is covalent.

Step9: Analyze K₂O

K (potassium) is a metal, O (oxygen) is a non - metal. So, the bond type is ionic.

Step10: Analyze AlF₃

Al (aluminum) is a metal, F (fluorine) is a non - metal. So, the bond type is ionic.

Step11: Analyze O₂

O (oxygen) is a non - metal. The bond within O₂ is covalent.

Step12: Analyze CuCl₂

Cu (copper) is a metal, Cl (chlorine) is a non - metal. So, the bond type is ionic.

Step13: Analyze NO₂

N (nitrogen) is a non - metal, O (oxygen) is a non - metal. So, the bond type is covalent.

Step14: Analyze CO₂

C (carbon) is a non - metal, O (oxygen) is a non - metal. So, the bond type is covalent.

Step15: Analyze HF

H (hydrogen) is a non - metal, F (fluorine) is a non - metal. So, the bond type is covalent.

Step16: Analyze Rb₂S

Rb (rubidium) is a metal, S (sulfur) is a non - metal. So, the bond type is ionic.

Step17: Analyze NBr₃

N (nitrogen) is a non - metal, Br (bromine) is a non - metal. So, the bond type is covalent.

Step18: Analyze Fe₂O₃

Fe (iron) is a metal, O (oxygen) is a non - metal. So, the bond type is ionic.

Step19: Analyze CCl₄

C (carbon) is a non - metal, Cl (chlorine) is a non - metal. So, the bond type is covalent.

Answer:

CompoundElement 1 (metal or non - metal?)Element 2 (metal or non - metal?)Bond Type
NaClNa = metalCl = non - metalionic
SO₂S = non - metalO = non - metalcovalent
P₆P = non - metal- (same element)covalent
MgBr₂Mg = metalBr = non - metalionic
CaOCa = metalO = non - metalionic
H₂OH = non - metalO = non - metalcovalent
K₂OK = metalO = non - metalionic
AlF₃Al = metalF = non - metalionic
O₂O = non - metalO = non - metalcovalent
CuCl₂Cu = metalCl = non - metalionic
NO₂N = non - metalO = non - metalcovalent
CO₂C = non - metalO = non - metalcovalent
HFH = non - metalF = non - metalcovalent
Rb₂SRb = metalS = non - metalionic
NBr₃N = non - metalBr = non - metalcovalent
Fe₂O₃Fe = metalO = non - metalionic
CCl₄C = non - metalCl = non - metalcovalent