Question

to rent a certain meeting room, a college charges a reservation fee of $15 and an additional fee of $6 per hour. the chemistry club wants to spend less than $75 on renting the room. what are the possible numbers of hours the chemistry club could rent the meeting room? use t for the number of hours. write your answer as an inequality, solved for t.

Explanation:

Step1: Set up the inequality

The total cost of renting the room is the reservation fee plus the cost per - hour times the number of hours. The reservation fee is $15$ and the cost per hour is $6$, and the number of hours is $t$. The club wants to spend less than $75$. So the inequality is $15 + 6t<75$.

Step2: Subtract 15 from both sides

To isolate the term with $t$, we subtract 15 from both sides of the inequality: $15 + 6t-15<75 - 15$, which simplifies to $6t<60$.

Step3: Divide both sides by 6

Dividing both sides of the inequality $6t<60$ by 6 gives $t < 10$.

Answer:

$t<10$