Question

rosa picked some oranges from her tree. she weighed each of the oranges. the results are shown in the line plot. what is the total weight of the two heaviest oranges?
weight of oranges (pounds)
a $2\frac{5}{8}$ pounds
b $1\frac{1}{2}$ pounds
c $2\frac{1}{2}$ pounds
d $3\frac{5}{8}$ pounds

Explanation:

Step1: Identify heaviest weights

The two heaviest orange weights are $1\frac{1}{8}$ pounds and $1\frac{2}{8}$ pounds.

Step2: Convert to improper fractions

$1\frac{1}{8} = \frac{9}{8}$, $1\frac{2}{8} = \frac{10}{8}$

Step3: Add the fractions

$\frac{9}{8} + \frac{10}{8} = \frac{19}{8}$

Step4: Simplify to mixed number

$\frac{19}{8} = 2\frac{3}{8}$? No, correct simplification: $\frac{9+10}{8}=\frac{19}{8}=2\frac{3}{8}$? Wait, no, $1\frac{1}{8}+1\frac{2}{8}=(1+1)+(\frac{1}{8}+\frac{2}{8})=2+\frac{3}{8}=2\frac{3}{8}$? Wait, no, $1\frac{2}{8}$ is $\frac{10}{8}$, $1\frac{1}{8}$ is $\frac{9}{8}$, sum is $\frac{19}{8}=2\frac{3}{8}$? Wait, no, the options: Option A is $2\frac{5}{8}$, Option C is $2\frac{1}{2}=\frac{20}{8}=2\frac{4}{8}$. Wait, correction: $1\frac{1}{8} = \frac{9}{8}$, $1\frac{2}{8}=\frac{10}{8}$, sum is $\frac{19}{8}=2\frac{3}{8}$? No, wait, $1\frac{1}{8} + 1\frac{2}{8} = 2 + \frac{3}{8} = 2\frac{3}{8}$? But that's not an option. Wait, no, the two heaviest are the maximum values, which are $1\frac{2}{8}$ and $1\frac{1}{8}$? Wait, no, the line plot: $1\frac{2}{8}$ has two X's, so the two heaviest oranges are both $1\frac{2}{8}$? Oh! I misread. The two heaviest oranges are the two at the highest weight, $1\frac{2}{8}$ pounds each.

Step1 (corrected): Identify two heaviest

The two heaviest oranges each weigh $1\frac{2}{8}$ pounds.

Step2 (corrected): Convert to improper fraction

$1\frac{2}{8} = \frac{10}{8}$

Step3 (corrected): Sum the two weights

$\frac{10}{8} + \frac{10}{8} = \frac{20}{8}$

Step4 (corrected): Simplify the fraction

$\frac{20}{8} = 2\frac{4}{8} = 2\frac{1}{2}$

Answer:

C. $2\frac{1}{2}$ pounds