QUESTION IMAGE
Question
science connection diagrams and formulas for four molecular compounds are shown. draw a diagram and write the formula for the next two compounds in the pattern.
(diagrams: cf₄, c₂f₆, c₃f₈, c₄f₁₀ with corresponding molecular structures)
Step1: Analyze the pattern of Carbon (C) atoms
Looking at the formulas: \( CF_4 \) (1 C), \( C_2F_6 \) (2 C), \( C_3F_8 \) (3 C), \( C_4F_{10} \) (4 C). The number of C atoms \( n \) follows \( n = 1,2,3,4,... \), so the next two will have \( n = 5 \) and \( n = 6 \).
Step2: Analyze the pattern of Fluorine (F) atoms
For \( n = 1 \), F = 4; \( n = 2 \), F = 6; \( n = 3 \), F = 8; \( n = 4 \), F = 10. The formula for F atoms is \( 2n + 2 \) (since \( 2(1)+2 = 4 \), \( 2(2)+2 = 6 \), etc.).
Step3: Determine the formula for \( n = 5 \)
For \( n = 5 \), number of F atoms: \( 2(5)+2 = 12 \). So the formula is \( C_5F_{12} \). The diagram will have 5 C atoms in a chain, each end C has 3 F atoms, and middle C (2nd, 3rd, 4th) have 2 F atoms each.
Step4: Determine the formula for \( n = 6 \)
For \( n = 6 \), number of F atoms: \( 2(6)+2 = 14 \). So the formula is \( C_6F_{14} \). The diagram will have 6 C atoms in a chain, each end C has 3 F atoms, and middle C (2nd, 3rd, 4th, 5th) have 2 F atoms each.
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The next two compounds are \( \boldsymbol{C_5F_{12}} \) (diagram: 5 - C chain, ends with 3 F each, middle C with 2 F each) and \( \boldsymbol{C_6F_{14}} \) (diagram: 6 - C chain, ends with 3 F each, middle C with 2 F each).