Question

section 5 - 5 voltage sources in series

1. series aiding is a term sometimes used to describe voltage sources of the same polarity in series. if a 5 v and a 9 v source are connected in this manner, what is the total voltage?
2. the term series opposing means that sources are in series with opposite polarities. if a 12 v and a 3 v battery are series - opposing, what is the total voltage?
3. determine the total source voltage in each circuit of figure 5 - 75.

figure 5 - 75

Explanation:

Step1: Solve question 27

For series - aiding voltage sources of the same polarity, we add the voltages. Given a 5 V and a 9 V source in series - aiding, the total voltage $V_{total}=5 + 9$.
$V_{total}=14$ V

Step2: Solve question 28

For series - opposing voltage sources, we subtract the magnitudes of the voltages. Given a 12 V and a 3 V battery in series - opposing, the total voltage $V_{total}=12−3$.
$V_{total}=9$ V

Step3: Solve question 29(a)

In the first circuit, we have 5 V, 10 V and 8 V sources in series - aiding. The total source voltage $V_{total}=5 + 10+8$.
$V_{total}=23$ V

Step4: Solve question 29(b)

In the second circuit, 50 V and 25 V are in series - aiding and 10 V is in series - opposing. The total source voltage $V_{total}=(50 + 25)-10$.
$V_{total}=65$ V

Answer:

1. 14 V
2. 9 V

29(a). 23 V
29(b). 65 V