Question

select the correct answer. if the coefficient 2 is placed in front of the product tetraiodine nonaoxide (i₄o₉), then, how many atoms of each element must be accounted for on the other side of the equation? a. 8 iodine atoms and 18 oxygen atoms b. 4 iodine atoms and 9 oxygen atoms c. 8 iodine atoms and 9 oxygen atoms d. 9 iodine atoms and 4 oxygen atoms e. 18 iodine atoms and 9 oxygen atoms

Explanation:

Step1: Analyze iodine atoms

The formula of the compound is $I_4O_9$. When the coefficient 2 is placed in front, for iodine ($I$), we have $2\times4 = 8$ iodine atoms.

Step2: Analyze oxygen atoms

For oxygen ($O$), with the coefficient 2 in front of $I_4O_9$, we have $2\times9=18$ oxygen atoms.

Answer:

A. 8 iodine atoms and 18 oxygen atoms