Question

select the subatomic composition of a selenium - 80 atom. refer to a periodic table. 34 protons, 46 neutrons, 46 electrons 46 protons, 34 neutrons, 34 electrons 46 protons, 34 neutrons, 46 electrons 34 protons, 46 neutrons, 34 electrons

Explanation:

Step1: Find atomic number of selenium

From periodic - table, selenium (Se) has atomic number \(Z = 34\). The atomic number is equal to the number of protons. So, number of protons \(p=34\).

Step2: Calculate number of neutrons

The mass number \(A = 80\). The formula for mass number is \(A=p + n\) (where \(n\) is number of neutrons). So, \(n=A - p=80 - 34 = 46\).

Step3: Determine number of electrons

For a neutral atom, number of electrons \(e\) is equal to number of protons. So, \(e = 34\).

Answer:

34 protons, 46 neutrons, 34 electrons