QUESTION IMAGE
Question
- sep interpret the data table records the motion of a toy car moving across a floor. the first two columns record positions and corresponding times. the third and fourth columns record speed and velocity for the four 1 - meter distances. some speed and velocity data are missing. complete the table. then explain how to calculate average speed and velocity.
position|time|speed in interval|velocity in interval
---|---|---|---
0 m east|0 s|—|—
1 m east|1 s|1 m/s|1 m/s east
2 m east|2 s||2 m/s east
3 m east|4 s|0.5 m/s|0.5 m/s east
4 m east|8 s|0.25 m/s||
- illustrate draw a diagram of the path the car took. add labels to show how the car’s speed and velocity changed. label where and when the car had uniform motion. write a caption comparing the velocity and speed of the car in terms of distance, displacement, and direction.
Step1: Calculate missing speed values
Speed is calculated as distance divided by time for each interval. For the second - third row: distance $d = 2 - 1=1$ m, time $t=2 - 1 = 1$ s, so speed $v=\frac{1}{1}=1$ m/s. For the fourth - fifth row: distance $d = 4 - 3 = 1$ m, time $t=8 - 4=4$ s, so speed $v=\frac{1}{4}=0.25$ m/s.
Step2: Calculate average speed
Average speed is total distance divided by total time. Total distance $D = 4$ m, total time $T = 8$ s. Average speed $v_{avg}=\frac{4}{8}=0.5$ m/s.
Step3: Calculate average velocity
Average velocity is total displacement divided by total time. Since the motion is in a straight - line (eastward) and displacement $\Delta x=4$ m (east), total time $T = 8$ s. Average velocity $\vec{v}_{avg}=\frac{4}{8}=0.5$ m/s east.
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| Position | Time | Speed in interval | Velocity in interval |
|---|---|---|---|
| 1 m east | 1 s | 1 m/s | 1 m/s east |
| 2 m east | 2 s | 1 m/s | 1 m/s east |
| 3 m east | 4 s | 0.5 m/s | 0.5 m/s east |
| 4 m east | 8 s | 0.25 m/s | 0.25 m/s east |
Average speed = 0.5 m/s. Average velocity = 0.5 m/s east.