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Question
- in a simple card game, player a wins a point if either a face card, a red prime number, or a black perfect - square number is drawn from a standard deck. otherwise, player b wins a point. assume aces do not count as ones! a) which player has the advantage in this game? support your answer with calculations and an explanation.
Step1: Calculate number of face - cards
A standard deck has 52 cards. There are 12 face - cards (4 Jacks, 4 Queens, 4 Kings). So the number of face - cards $n_{face}=12$.
Step2: Calculate number of red prime - numbered cards
Prime numbers on cards (2, 3, 5, 7) and red cards are hearts and diamonds. For each suit, there are 4 prime - numbered cards. So number of red prime - numbered cards $n_{red\ prime}=2\times4 = 8$.
Step3: Calculate number of black perfect - square numbered cards
Perfect square numbers on cards are 4 and 9. Black suits are spades and clubs. So number of black perfect - square numbered cards $n_{black\ square}=2\times2=4$.
Step4: Calculate total favorable outcomes
Using the addition principle for non - overlapping events, the total number of favorable outcomes for Player A, $n=n_{face}+n_{red\ prime}+n_{black\ square}=12 + 8+4=24$.
Step5: Calculate probabilities
The probability that Player A wins, $P(A)=\frac{24}{52}=\frac{6}{13}$. The probability that Player B wins, $P(B)=1 - P(A)=1-\frac{6}{13}=\frac{7}{13}$.
Since $\frac{7}{13}>\frac{6}{13}$, Player B has the advantage.
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Player B has the advantage.