Question

and her sister went together to get haircuts. tara got 2 2/12 inches cut of 1/4 of an inch cut off. compared to her sister, how much more hair did ta rite your answer as a fraction or as a whole or mixed number. inches

Explanation:

Step1: Simplify Tara's cut length

First, simplify \( 2\frac{2}{12} \). The fraction \( \frac{2}{12} \) simplifies to \( \frac{1}{6} \), so \( 2\frac{2}{12}=2\frac{1}{6} \).

Step2: Convert to common denominator

We need to find the difference between \( 2\frac{1}{6} \) and \( \frac{1}{4} \). The common denominator of 6 and 4 is 12. Convert \( 2\frac{1}{6} \) to twelfths: \( 2\frac{1}{6}=2\frac{2}{12} \) (since \( \frac{1}{6}=\frac{2}{12} \)) and \( \frac{1}{4}=\frac{3}{12} \). Wait, no, actually, we have \( 2\frac{1}{6} \) as Tara's cut and \( \frac{1}{4} \) as her sister's. Wait, maybe I misread. Wait, the problem: Tara got \( 2\frac{2}{12} \) inches cut, her sister got \( \frac{1}{4} \) inch cut. So we need to subtract \( \frac{1}{4} \) from \( 2\frac{2}{12} \).
First, simplify \( 2\frac{2}{12} \) to \( 2\frac{1}{6} \) (dividing numerator and denominator by 2). Now, convert \( 2\frac{1}{6} \) and \( \frac{1}{4} \) to have a common denominator. The least common multiple of 6 and 4 is 12. So \( 2\frac{1}{6}=2\frac{2}{12} \) (because \( \frac{1}{6}=\frac{2}{12} \)) and \( \frac{1}{4}=\frac{3}{12} \). Wait, but \( 2\frac{2}{12} \) is \( 2 + \frac{2}{12} \), and we are subtracting \( \frac{3}{12} \). Wait, no, that can't be, because \( \frac{2}{12} < \frac{3}{12} \). Wait, maybe I misread the problem. Wait, maybe the sister's cut is \( 1\frac{1}{4} \)? Wait, the original text: "Tara got 2 2/12 inches cut of t 1/4 of an inch cut off." Wait, maybe a typo. Wait, probably, Tara got \( 2\frac{2}{12} \) inches cut, her sister got \( \frac{1}{4} \) inch? No, that doesn't make sense. Wait, maybe "her sister got 1/4 of an inch cut off" and Tara got \( 2\frac{2}{12} \). So the difference is \( 2\frac{2}{12}-\frac{1}{4} \).
Wait, let's re - do:
First, simplify \( 2\frac{2}{12} \): \( \frac{2}{12}=\frac{1}{6} \), so \( 2\frac{2}{12}=2\frac{1}{6} \).
Now, convert \( 2\frac{1}{6} \) to an improper fraction: \( 2\frac{1}{6}=\frac{13}{6} \), and \( \frac{1}{4} \) is as is.
Find a common denominator, which is 12. \( \frac{13}{6}=\frac{26}{12} \), \( \frac{1}{4}=\frac{3}{12} \).
Now subtract: \( \frac{26}{12}-\frac{3}{12}=\frac{23}{12}=1\frac{11}{12} \). Wait, no, that can't be. Wait, maybe the sister's cut is \( 1\frac{1}{4} \)? Wait, the original text is a bit garbled. Wait, let's look again: "and her sister went together to get haircuts. Tara got 2 2/12 inches cut of t 1/4 of an inch cut off. Compared to her sister, how much more hair did Ta" Wait, maybe it's "Tara got \( 2\frac{2}{12} \) inches cut, her sister got \( \frac{1}{4} \) inch cut". Wait, but \( 2\frac{2}{12} \) is about 2.166 inches, and \( \frac{1}{4} \) is 0.25 inches. The difference would be \( 2\frac{2}{12}-\frac{1}{4} \).
Wait, let's do it step by step correctly.
First, simplify \( 2\frac{2}{12} \):
\( 2\frac{2}{12}=2+\frac{2}{12}=2+\frac{1}{6}=\frac{12 + 1}{6}=\frac{13}{6} \) (improper fraction).
Her sister's cut: \( \frac{1}{4} \).
Find the difference: \( \frac{13}{6}-\frac{1}{4} \).
Common denominator is 12:
\( \frac{13}{6}=\frac{13\times2}{6\times2}=\frac{26}{12} \)
\( \frac{1}{4}=\frac{1\times3}{4\times3}=\frac{3}{12} \)
Subtract: \( \frac{26}{12}-\frac{3}{12}=\frac{23}{12}=1\frac{11}{12} \). Wait, but that seems like a lot. Wait, maybe the sister's cut is \( 1\frac{1}{4} \)? Wait, maybe a typo in the problem. Wait, the original problem: "Tara got 2 2/12 inches cut of t 1/4 of an inch cut off" – maybe it's "Tara got \( 2\frac{2}{12} \) inches cut, her sister got \( 1\frac{1}{4} \) inches cut". Let's check that. If sister got \( 1\frac{1}{4} \), then:
\( 2\frac{2}{12}-1\frac{1}{4} \)
Simplify \( 2\frac{2}{12}=2\frac{1}{6} \), \( 1\frac{1}{4}=1\frac{3}{12}=1\frac{1}{4} \)
Common denominator 12: \( 2\frac{2}{12}-1\frac{3}{12} \)
Convert to improper fractions: \( \frac{26}{12}-\frac{15}{12}=\frac{11}{12} \). No, that's not. Wait, maybe I misread the problem. Let's re - examine the user's image description: "and her sister went together to get haircuts. Tara got 2 2/12 inches cut of t 1/4 of an inch cut off. Compared to her sister, how much more hair did Ta" – maybe "Tara got \( 2\frac{2}{12} \) inches cut, her sister got \( \frac{1}{4} \) inch cut". So the difference is \( 2\frac{2}{12}-\frac{1}{4} \).
Simplify \( 2\frac{2}{12}=2\frac{1}{6} \).
\( 2\frac{1}{6}-\frac{1}{4} \)
Convert to twelfths: \( 2\frac{2}{12}-\frac{3}{12} \)
But \( 2\frac{2}{12} \) is \( 2 + \frac{2}{12} \), and we are subtracting \( \frac{3}{12} \), so we need to borrow 1 from the 2: \( 1 + \frac{12 + 2}{12}-\frac{3}{12}=1+\frac{14}{12}-\frac{3}{12}=1+\frac{11}{12}=1\frac{11}{12} \). So the answer is \( 1\frac{11}{12} \) inches. Wait, but maybe the problem was supposed to be Tara got \( 2\frac{2}{12} \) and sister got \( 1\frac{1}{4} \), but with the given text, it's \( \frac{1}{4} \). So proceeding with the given text:
Tara's cut: \( 2\frac{2}{12}=2\frac{1}{6}=\frac{13}{6} \)
Sister's cut: \( \frac{1}{4} \)
Difference: \( \frac{13}{6}-\frac{1}{4}=\frac{26 - 3}{12}=\frac{23}{12}=1\frac{11}{12} \)

Answer:

\( 1\frac{11}{12} \)