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Question
a spinner is divided into two equal parts, one red and one blue. the set of possible outcomes when the spinner is spun twice is s = {rr, rb, br, bb}. let x represent the number of times blue occurs. which of the following is the probability distribution, ( p_x(x) )?
| ( x ) | ( p_x(x) ) |
|---|---|
| 1 | 0.5 |
| 2 | 0.25 |
| ( x ) | ( p_x(x) ) |
|---|---|
| 1 | 0.33 |
| 2 | 0.33 |
| ( x ) | ( p_x(x) ) |
|---|---|
| 1 | 0.5 |
| 2 | 0 |
Step1: Determine possible values of \( X \)
The spinner is spun twice, and \( X \) is the number of times blue occurs. So \( X \) can be 0, 1, or 2.
Step2: Calculate \( P(X = 0) \)
\( X = 0 \) means no blue occurs, so the outcome is \( RR \). There are 4 total outcomes (\( S=\{RR, RB, BR, BB\} \)), so \( P(X = 0)=\frac{\text{Number of } RR}{\text{Total outcomes}}=\frac{1}{4} = 0.25 \).
Step3: Calculate \( P(X = 1) \)
\( X = 1 \) means blue occurs once. The outcomes are \( RB \) and \( BR \). So the number of favorable outcomes is 2. Then \( P(X = 1)=\frac{2}{4}=0.5 \).
Step4: Calculate \( P(X = 2) \)
\( X = 2 \) means blue occurs twice, so the outcome is \( BB \). The number of favorable outcomes is 1. Thus \( P(X = 2)=\frac{1}{4}=0.25 \).
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The first probability distribution table (with \( X = 0 \) having \( P_X(x)=0.25 \), \( X = 1 \) having \( P_X(x)=0.5 \), and \( X = 2 \) having \( P_X(x)=0.25 \))