Question

1. the spinner shown is divided into congruent sections. if the spinner is spun one time, what is the probability of the arrow not landing on a section labeled odd number? a $\frac{2}{5}$ b $\frac{1}{10}$ c $\frac{3}{10}$ d $\frac{7}{10}$

Explanation:

Step1: Count total sections

Count all congruent spinner sections: $1+4+2+4+1+2+2+3+4+2 = 10$

Step2: Count odd-numbered sections

Identify odd labels (1,3) and count: $1+1+3 = 3$

Step3: Calculate non-odd section count

Subtract odd count from total: $10 - 3 = 7$

Step4: Compute probability

Divide non-odd count by total: $\frac{7}{10}$

Answer:

D. $\frac{7}{10}$