Question

stefano accidentally dropped his sunglasses off the edge of a canyon as he was looking down. the height, h(t), in meters (as it relates to sea level), of the sunglasses after t seconds, is shown in the table. during its descent, the pair of sunglasses passed by a climber in the canyon 6 seconds after stefano dropped them. to the nearest meter, what is difference in elevation between stefano and the climber? height of sunglasses over time

t	h(t)
0	10
1	5.1
2	-9.6
3	-34.1
4	-68.4
5	-112.5
6	-166.4
7	-230.1

o 166 meters
o 176 meters
o 230 meters
o 240 meters

Explanation:

Step1: Determine Stefano's height

When $t = 0$, the height of the sunglasses $h(0)=10$ meters. This represents Stefano's height relative to sea - level when he dropped the sunglasses.

Step2: Determine climber's height

When $t = 6$, the height of the sunglasses $h(6)=- 166.4$ meters. This is the height of the sunglasses when they pass the climber.

Step3: Calculate the difference in elevation

The difference $\Delta h$ between Stefano's height and the climber's height is $h(0)-h(6)$. So, $\Delta h=10-(-166.4)=10 + 166.4 = 176.4\approx176$ meters.

Answer:

176 meters