Question

steven hit a golf ball and recorded its height in feet, ( h(t) ), after ( t ) seconds.

( t )	1	1.5	2	2.5	3	3.5	4
( h(t) )	63	82.5	94	97.5	93	80.5	60

according to the table, what is the average rate of change over the interval (2.5, 4)?
a. 37.5 feet per second
b. -25 feet per second
c. 25 feet per second
d. -37.5 feet per second

Explanation:

Step1: Recall average rate formula

The average rate of change of a function $h(t)$ over interval $[a,b]$ is $\frac{h(b)-h(a)}{b-a}$.

Step2: Identify values from table

For $a=2.5$, $h(a)=97.5$; for $b=4$, $h(b)=60$.

Step3: Substitute into formula

$\frac{60 - 97.5}{4 - 2.5} = \frac{-37.5}{1.5}$

Step4: Calculate the result

$\frac{-37.5}{1.5} = -25$

Answer:

B. -25 feet per second