Question

stoichiometry & limiting reproblem5. $2\\ hi + ca(oh)_2 \
ightarrow cal_2 + 2\\ h_2o$if 7.45 grams of hi (molar mass 127.91 g/mol) are reacted, how many grams of $ca(oh)_2$ (molar mass 74.09 g/mol) will also be reacted?- show correct answe

Explanation:

Step1: Calculate moles of HI

Moles of HI = $\frac{\text{Mass of HI}}{\text{Molar mass of HI}} = \frac{7.45\ \text{g}}{127.91\ \text{g/mol}} \approx 0.05824\ \text{mol}$

Step2: Find mole ratio of HI to Ca(OH)₂

From the balanced equation $2\text{HI} + \text{Ca(OH)}_2
ightarrow \text{CaI}_2 + 2\text{H}_2\text{O}$, the mole ratio is $\frac{1\ \text{mol Ca(OH)}_2}{2\ \text{mol HI}}$

Step3: Calculate moles of Ca(OH)₂

Moles of Ca(OH)₂ = $0.05824\ \text{mol HI} \times \frac{1\ \text{mol Ca(OH)}_2}{2\ \text{mol HI}} = 0.02912\ \text{mol}$

Step4: Convert moles to grams of Ca(OH)₂

Mass of Ca(OH)₂ = $\text{Moles} \times \text{Molar mass} = 0.02912\ \text{mol} \times 74.09\ \text{g/mol} \approx 2.16\ \text{g}$

Answer:

2.16 grams