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the students in marlys math class recorded the dimensions of their bedr…

Question

the students in marlys math class recorded the dimensions of their bedrooms in a frequency table. bedroom areas
area (sq. ft) number of bedrooms
60 ≤ a < 80 4
80 ≤ a < 100 6
100 ≤ a < 120 5
120 ≤ a < 140 3
140 ≤ a < 160 1
create a histogram to represent the data. which statement is most likely true about the mean and the median of the data?
the histogram is right - skewed, so the mean is less than the median.
the histogram is right - skewed, so the mean is greater than the median.
the histogram is left - skewed, so the mean is less than the median.
the histogram is left - skewed, so the mean is greater than the median.

Explanation:

Step1: Analyze skewness

As the frequency decreases as the area increases (4, 6, 5, 3, 1 for increasing area intervals), the histogram will be right - skewed.

Step2: Recall mean - median relationship for skewed data

In a right - skewed distribution, the tail on the right (higher values) pulls the mean in that direction. So the mean is greater than the median.

Answer:

The histogram is right - skewed, so the mean is greater than the median.