Question

suppose that e and f are two events and that n(e and f)=230 and n(e)=600. what is p(f|e)?
p(f|e)≈ (round to three decimal places as needed.)

Explanation:

Step1: Recall the formula for conditional probability

The formula for conditional probability is $P(F|E)=\frac{P(E\cap F)}{P(E)}$. In terms of the number of elements, if $N(E)$ is the number of elements in event $E$ and $N(E\cap F)$ is the number of elements in the intersection of $E$ and $F$, then $P(F|E)=\frac{N(E\cap F)}{N(E)}$.

Step2: Substitute the given values

We are given that $N(E\cap F) = 230$ and $N(E)=600$. Substituting these values into the formula, we get $P(F|E)=\frac{230}{600}$.

Step3: Calculate and round

$\frac{230}{600}\approx0.383$.

Answer:

$0.383$