Question

suppose you are performing an acid/base extraction. after one of the steps, you have collected a naoh extract containing the pictured phenolate. next, you add hcl to the layer. what are the products of the hcl addition? select one or more

Explanation:

Step1: Understand the reaction

The phenolate ion (\(Ar - O^-\)) in the \(NaOH\) extract will react with \(HCl\) (a strong - acid). The reaction is an acid - base reaction where the phenolate ion acts as a base and accepts a proton (\(H^+\)) from \(HCl\).

Step2: Write the reaction equation

\(Ar - O^-+HCl
ightarrow Ar - OH + Cl^-\)

Answer:

The product of the addition of \(HCl\) to the phenolate - containing layer is the neutral phenol compound (the third - option structure with an \(OH\) group on the aromatic ring). So the answer is the option with the structure having a hydroxyl (\(OH\)) group on the benzene ring instead of the phenolate (\(O^-\)) group.