Question

the table shows the distribution, by age and gender, of the 30.7 million people in a certain region who live alone. use the data in the table to find the probability that a randomly selected person in the region is a woman in the 18-24 age range living alone.| | ages 18-24 | ages 25-34 | ages 35-44 | ages 45-64 | ages 65-74 | ages ≥75 | total || ---- | ---- | ---- | ---- | ---- | ---- | ---- | ---- || man | 0.8 | 2.6 | 2.8 | 4.4 | 1.6 | 1.2 | 13.4 || woman | 0.6 | 1.9 | 1.5 | 6.0 | 2.5 | 4.8 | 17.3 || total | 1.4 | 4.5 | 4.3 | 10.4 | 4.1 | 6.0 | 30.7 |the probability is $square$.(type an integer or decimal rounded to the nearest hundredth as needed.)

Explanation:

Step1: Identify target and total values

Target (women 18-24 alone) = 0.6; Total people = 30.7

Step2: Calculate probability

Probability = $\frac{\text{Target Value}}{\text{Total Value}}$ = $\frac{0.6}{30.7}$

Step3: Round to nearest hundredth

$\frac{0.6}{30.7} \approx 0.0195 \approx 0.02$

Answer:

0.02