Question

this table shows the time and distance a vehicle traveling at a constant speed has moved past a set point.
elapsed time (seconds) | distance traveled (meters)
15 | 360
30 | 720
45 | 1,080
what is the distance traveled, in meters, at the instant when the elapsed time is 1 minute and 35 seconds?

1. mr. warner bought a camera at a 25% discount off the regular price. the regular price was $66. how much did mr. warner pay for the camera, not including tax?
2. angela earns $500 per month.

• usually, she saves 15% of her earnings.
• this month, she saved $80.

how many more dollars did angela save this month than she usually saves?

Explanation:

Question 1 (Vehicle Distance)

Step1: Find the speed (constant)

Speed \( v = \frac{\text{Distance}}{\text{Time}} \). Using first row: \( v = \frac{360}{15} = 24 \) m/s.

Step2: Convert time to seconds

1 minute 35 seconds = \( 60 + 35 = 95 \) seconds.

Step3: Calculate distance

Distance \( d = v \times t = 24 \times 95 = 2280 \) meters.

Step1: Find discount amount

Discount = 25% of $66. \( 0.25 \times 66 = 16.5 \) dollars.

Step2: Subtract discount from regular price

Amount paid = \( 66 - 16.5 = 49.5 \) dollars.

Step1: Find usual savings

Usual savings = 15% of $500. \( 0.15 \times 500 = 75 \) dollars.

Step2: Find difference in savings

Difference = \( 80 - 75 = 5 \) dollars.

Answer:

2280

Question 11 (Camera Price)