Question

the table summarizes results from 984 pedestrian deaths that were caused by automobile accidents.

driver intoxicated?	pedestrian intoxicated?
yes	60	69
no	252	603

if one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was intoxicated or the driver was not intoxicated. please enter a decimal to 4 decimal places.
probability =
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Explanation:

Step1: Find total number of cases

The total number of pedestrian - deaths is \(60 + 69+252 + 603=984\).

Step2: Find number of favorable cases

Let \(A\) be the event that the pedestrian was intoxicated and \(B\) be the event that the driver was not intoxicated.
The number of cases where the pedestrian was intoxicated is \(60 + 252=312\).
The number of cases where the driver was not intoxicated is \(252+603 = 855\).
The number of cases where the pedestrian was intoxicated and the driver was not intoxicated is \(252\).
Using the formula \(P(A\cup B)=P(A)+P(B)-P(A\cap B)\), we have \(n(A\cup B)=312 + 855-252=915\).

Step3: Calculate the probability

The probability \(P=\frac{n(A\cup B)}{n(\text{total})}=\frac{915}{984}\approx0.9390\).

Answer:

\(0.9390\)