Question

temperature. suppose there is a 1.5°f drop in temperature for every thousand feet that an airplane climbs into the sky. if the temperature on the ground is 48.5°f, what will be the temperature when the plane reaches an altitude of 9,000 ft?
the temperature will be $square$°f. (type an integer or a decimal.)

Explanation:

Step1: Calculate number of thousand - feet intervals

First, divide the altitude (9000 ft) by 1000. The number of thousand - feet intervals $n=\frac{9000}{1000}=9$.

Step2: Calculate temperature drop

Since there is a $1.5^{\circ}F$ drop for each thousand - feet interval, the total temperature drop $\Delta T = 1.5\times n$. Substituting $n = 9$ into the formula, we get $\Delta T=1.5\times9 = 13.5^{\circ}F$.

Step3: Calculate final temperature

The temperature on the ground is $48.5^{\circ}F$. The temperature at altitude $T = 48.5-\Delta T$. Substituting $\Delta T = 13.5^{\circ}F$ into the formula, we have $T=48.5 - 13.5=35^{\circ}F$.

Answer:

$35$