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question 8
$\frac{4^{x}}{4^{y}} = 4^{x}-4^{y}$
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false
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Explanation:

Step1: Apply exponent - division rule

According to the rule $\frac{a^m}{a^n}=a^{m - n}$, for $\frac{4^x}{4^y}$, we have $\frac{4^x}{4^y}=4^{x - y}$.

Step2: Compare with right - hand side

The right - hand side of the given equation is $4^x-4^y$. Since $4^{x - y}
eq4^x - 4^y$ in general. For example, if $x = 2$ and $y = 1$, $\frac{4^2}{4^1}=\frac{16}{4}=4$, and $4^2-4^1=16 - 4 = 12$.

Answer:

False