Question

there is 1 red gumdrop and 4 green gumdrops in a small jar. also, 2 pieces of butterscotch candy and 3 pieces of cinnamon candy are in another jar. if craig draws one piece of candy from each jar without looking, whats the probability that he will get a red gumdrop and a piece of butterscotch candy? a. \\(\frac{2}{25}\\) b. \\(\frac{4}{25}\\) c. \\(\frac{3}{10}\\) d. \\(\frac{3}{25}\\)

Explanation:

Step1: Find total gumdrops in first jar

Total gumdrops = 1 (red) + 4 (green) = 5. Probability of red gumdrop: \( \frac{1}{5} \).

Step2: Find total candies in second jar

Total candies = 2 (butterscotch) + 3 (cinnamon) = 5. Probability of butterscotch: \( \frac{2}{5} \).

Step3: Multiply the two probabilities

Since the events are independent, multiply the probabilities: \( \frac{1}{5} \times \frac{2}{5} = \frac{2}{25} \).

Answer:

A. \( \frac{2}{25} \)