Question

there is 1 red gumdrop and 4 green gumdrops in a small jar. also, 2 pieces of butterscotch candy and 3 pieces of cinnamon candy are in another jar. if craig draws one piece of candy from each jar without looking, whats the probability that he will get a red gumdrop and a piece of butterscotch candy? a. $\frac{1}{10}$ b. $\frac{1}{25}$ c. $\frac{1}{5}$ d. $\frac{1}{20}$

Explanation:

Step1: Calculate probability of red gumdrop

There is 1 red gumdrop and 4 green gumdrops, so total gumdrops are $1 + 4=5$. Probability of getting red gumdrop $P(R)=\frac{1}{5}$.

Step2: Calculate probability of butterscotch candy

There are 2 pieces of butterscotch candy and 3 pieces of cinnamon candy, so total candies are $2 + 3 = 5$. Probability of getting butterscotch candy $P(B)=\frac{2}{5}$.

Step3: Calculate combined probability

Since the two events are independent, the probability of both events occurring is the product of their individual probabilities. So $P = P(R)\times P(B)=\frac{1}{5}\times\frac{2}{5}=\frac{2}{25}$.

Answer:

C. $\frac{2}{25}$