Question

(\frac{2}{4} + \frac{2}{4} =) (\boxed{\frac{4}{4}})

（three circles divided into four parts each, first two with two parts shaded, third with four parts shaded）

(\frac{1}{4} + \frac{1}{4} =) (square)

（three circles divided into eight parts each, first two with one part shaded, third unshaded）

(\frac{2}{8} + \frac{2}{8} =) (square)

（three circles divided into eight parts each, first two with two parts shaded, third unshaded）

Explanation:

Step1: Solve \(\frac{1}{4} + \frac{1}{4}\)

When adding fractions with the same denominator, we add the numerators and keep the denominator the same. So, \(\frac{1}{4} + \frac{1}{4} = \frac{1 + 1}{4} = \frac{2}{4}\) (which can also be simplified to \(\frac{1}{2}\), but let's follow the addition rule first).

Step2: Solve \(\frac{2}{8} + \frac{2}{8}\)

Again, for fractions with the same denominator, add the numerators. So, \(\frac{2}{8} + \frac{2}{8} = \frac{2 + 2}{8} = \frac{4}{8}\) (which simplifies to \(\frac{1}{2}\) as well, but we'll present the result of the addition here).

Answer:

For \(\frac{1}{4} + \frac{1}{4}\), the answer is \(\frac{2}{4}\) (or \(\frac{1}{2}\)).
For \(\frac{2}{8} + \frac{2}{8}\), the answer is \(\frac{4}{8}\) (or \(\frac{1}{2}\)).