Question

tina found some chalk near the board. she measured the length of each piece of chalk.

chalk near the board
chart with x marks at 4, 5, 6, 7, 8 centimeters
length (centimeters)

how many pieces of chalk were longer than 5 centimeters?

\boxed{} pieces of chalk

Explanation:

Step1: Identify chalk lengths >5 cm

Chalk lengths: 6,7,8 cm (since >5). Count X's for each:

• 6 cm: 4 X's
• 7 cm: 2 X's
• 8 cm: 1 X's

Step2: Sum the counts

Add the number of X's: \( 4 + 2 + 1 = 7 \)? Wait, wait, recheck:
Wait, 6 cm: let's count the X's. The third column (6) has 4? Wait no, looking at the graph:

• 4 cm: 3 X's
• 5 cm: 4 X's
• 6 cm: 4 X's? Wait no, original graph:

Wait the first column (4) has 3 X's (rows 2,3,4), second (5) has 4 X's (rows 1 - 4), third (6) has 4 X's? Wait no, the user's graph:

Wait the X's:

4 cm: 3 (three X's: row 2,3,4)

5 cm: 4 (four X's: row 1 - 4)

6 cm: 4 (four X's: row 1 - 4)

7 cm: 2 (two X's: row 3,4)

8 cm: 1 (one X: row 4)

Wait no, the problem is "longer than 5 cm", so lengths 6,7,8 cm.

So 6 cm: count the X's. Let's see the third column (6) has 4? Wait the original graph:

Looking at the vertical X's:

For 4 cm: 3 X's (three marks)

5 cm: 4 X's (four marks)

6 cm: 4 X's (four marks)

7 cm: 2 X's (two marks)

8 cm: 1 X (one mark)

Wait, no, let's count again:

• Length 6 cm: how many X's? The third column (6) has 4 X's? Wait the first column (4) has 3 (rows 2,3,4), second (5) has 4 (rows 1 - 4), third (6) has 4 (rows 1 - 4), fourth (7) has 2 (rows 3,4), fifth (8) has 1 (row 4).

Wait, "longer than 5 cm" means length >5, so 6,7,8.

So 6 cm: 4 X's

7 cm: 2 X's

8 cm: 1 X

Total: 4 + 2 + 1 = 7? Wait no, wait 6 cm: let's count the X's. The third column (6) has 4? Wait the user's graph:

Wait the X's are stacked:

For 4: three X's (vertical: three)

5: four X's (vertical: four)

6: four X's (vertical: four)

7: two X's (vertical: two)

8: one X (vertical: one)

Wait, no, maybe I miscounted. Let's list each length:

• 4 cm: 3 pieces (X count: 3)

• 5 cm: 4 pieces (X count: 4)

• 6 cm: 4 pieces (X count: 4)

• 7 cm: 2 pieces (X count: 2)

• 8 cm: 1 piece (X count: 1)

So longer than 5 cm: 6,7,8. So 4 (6cm) + 2 (7cm) + 1 (8cm) = 7? Wait no, 4 + 2 + 1 = 7? Wait 4+2=6, 6+1=7. Wait but maybe I made a mistake. Wait let's check again:

Wait the third column (6) has 4 X's? Let's see the original graph:

The first column (4) has 3 X's (three green X's), second (5) has 4, third (6) has 4, fourth (7) has 2, fifth (8) has 1. So 6 cm: 4, 7 cm: 2, 8 cm: 1. Sum: 4+2+1=7. Wait but maybe the third column is 4? Wait maybe I miscounted. Wait let's count the X's for each length:

• 4 cm: 3 (rows 2,3,4)

• 5 cm: 4 (rows 1,2,3,4)

• 6 cm: 4 (rows 1,2,3,4)

• 7 cm: 2 (rows 3,4)

• 8 cm: 1 (row 4)

Yes, so longer than 5 cm: 6,7,8. So 4 + 2 + 1 = 7. Wait but maybe the answer is 7? Wait no, wait 6 cm: 4, 7 cm: 2, 8 cm: 1. 4+2=6, 6+1=7. So total 7.

Wait, but let's re-express:

Length 6: 4 pieces

Length 7: 2 pieces

Length 8: 1 piece

Total: 4 + 2 + 1 = 7.

Answer:

7