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7) two planes take off from the same airstrip. the first plane flies we…

Question

  1. two planes take off from the same airstrip. the first plane flies west for 150 miles and then flies 30° south of west for 220 miles. the second plane flies east for 220 miles and then flies ( x^circ ) south of east for 150 miles. if ( x < 30 ), which plane is farther from the airstrip after the second leg? justify your answer.

Explanation:

Step1: Define displacement vectors for Plane 1

Let the airstrip be at the origin. West is $-x$ direction, South is $-y$ direction.
First leg: $\vec{v_1} = \langle -150, 0
angle$
Second leg: $220$ miles at $30^\circ$ south of west:
$\vec{v_2} = \langle -220\cos30^\circ, -220\sin30^\circ
angle$
Total displacement $\vec{D_1} = \vec{v_1}+\vec{v_2} = \langle -150 - 220\cos30^\circ, 0 - 220\sin30^\circ
angle$

Step2: Calculate magnitude for Plane 1

Use distance formula $|\vec{D}| = \sqrt{D_x^2 + D_y^2}$:

$$\begin{align*} |\vec{D_1}| &= \sqrt{(-150 - 220\cos30^\circ)^2 + (-220\sin30^\circ)^2}\\ &= \sqrt{150^2 + 2\cdot150\cdot220\cos30^\circ + (220\cos30^\circ)^2 + (220\sin30^\circ)^2}\\ &= \sqrt{150^2 + 220^2 + 2\cdot150\cdot220\cos30^\circ} \end{align*}$$

(Used $\cos^2\theta+\sin^2\theta=1$)

Step3: Define displacement vectors for Plane 2

First leg: $\vec{u_1} = \langle 220, 0
angle$
Second leg: $150$ miles at $x^\circ$ south of east:
$\vec{u_2} = \langle 150\cos x^\circ, -150\sin x^\circ
angle$
Total displacement $\vec{D_2} = \vec{u_1}+\vec{u_2} = \langle 220 + 150\cos x^\circ, 0 - 150\sin x^\circ
angle$

Step4: Calculate magnitude for Plane 2

$$\begin{align*} |\vec{D_2}| &= \sqrt{(220 + 150\cos x^\circ)^2 + (-150\sin x^\circ)^2}\\ &= \sqrt{220^2 + 2\cdot220\cdot150\cos x^\circ + (150\cos x^\circ)^2 + (150\sin x^\circ)^2}\\ &= \sqrt{150^2 + 220^2 + 2\cdot150\cdot220\cos x^\circ} \end{align*}$$

Step5: Compare the two magnitudes

The only differing term is $\cos30^\circ$ vs $\cos x^\circ$. Since $x<30^\circ$, and $\cos\theta$ decreases as $\theta$ increases in $0^\circ$ to $90^\circ$, so $\cos x^\circ > \cos30^\circ$.
Thus $|\vec{D_2}| > |\vec{D_1}|$.

Answer:

The second plane is farther from the airstrip.