Question

the two - way table shows the number of houses on the market in the castillos price range.

	1 bedroom	2 bedrooms	3 bedrooms	4 bedrooms	total
2 bathrooms	0	6	24	0	30
3 bathrooms	0	18	16	56	90
total	67	45	40	56	208

what is the probability that a randomly selected house with 2 bathrooms has 3 bedrooms?
○ 0.2
○ 0.4
○ 0.6
○ 0.8

Explanation:

Step1: Identify relevant counts

From the table, number of houses with 2 bathrooms and 3 bedrooms is 24. Total number of houses with 2 bathrooms is 30.

Step2: Calculate probability

Probability = (Number of 2 - bathroom, 3 - bedroom houses) / (Total number of 2 - bathroom houses) = $\frac{24}{30}$ = 0.8? Wait, no, wait. Wait, 24 divided by 30: 24/30 = 0.8? Wait, no, 24 divided by 30 is 0.8? Wait, 24 ÷ 30 = 0.8? Wait, no, 24/30 = 0.8? Wait, 24 divided by 30: 30 goes into 24 zero, 30 goes into 240 eight times. So 0.8? Wait, but let me check again. The row for 2 Bathrooms: total is 30. The number of 3 Bedrooms in 2 Bathrooms is 24. So 24/30 = 0.8. Wait, but the options include 0.8. Wait, but let me check the table again. 2 Bathrooms row: 0 (1 bedroom), 6 (2 bedrooms), 24 (3 bedrooms), 0 (4 bedrooms). Total is 0+6+24+0=30. So yes, 24/30=0.8. Wait, but the options have 0.8 as an option. Wait, but let me confirm. Probability is favorable over total in the condition. The condition is "with 2 bathrooms", so total is 30. Favorable is 24 (3 bedrooms and 2 bathrooms). So 24/30=0.8. So the answer is 0.8. Wait, but let me check the calculation again. 24 divided by 30: divide numerator and denominator by 6: 4/5=0.8. Yes. So the probability is 0.8.

Answer:

0.8 (corresponding to the option with 0.8, e.g., if the options are as given, the correct one is the last option: 0.8)