Question

unit exam-gravitational/electrostatic forces

	set 1	set 2
charge 1	-4 c	+3 c
charge 2	-4 c	-1 c
distance	6 x 10⁻⁸ m	6 x 10⁻⁸ m

which set has a coulombic attraction force?
remember : $f_c = \frac{k(q_1q_2)}{d^2}$
the sets exhibits an equivalent type of coulombic force.
set 2
set 1

Explanation:

Step1: Recall Coulomb's Law for Force Type

Coulombic force: like charges repel, opposite charges attract. So we check the sign of each charge pair (product of charges: positive for like, negative for opposite).

Step2: Analyze Set 1 Charges

Charge 1: \(-4\) C, Charge 2: \(-4\) C.
Product: \((-4)\times(-4) = 16\) (positive, like charges → repulsion).

Step3: Analyze Set 2 Charges

Charge 1: \(+3\) C, Charge 2: \(-1\) C.
Product: \((+3)\times(-1) = -3\) (negative, opposite charges → attraction).

Answer:

Set 2