Question

from unit 1, lesson 15 here are statistics for the length of some frog jumps in inches: the mean is 41 inches the median is 39 inches the standard deviation is about 9.6 inches the iqr is 5.5 inches. how does each statistic change if the length of the jumps are measured in feet instead of inches?

Explanation:

Step1: Recall conversion factor

1 foot = 12 inches. To convert from inches to feet, divide by 12.

Step2: Convert mean

The mean in feet is $\frac{41}{12}\approx3.42$ feet.

Step3: Convert median

The median in feet is $\frac{39}{12} = 3.25$ feet.

Step4: Convert standard - deviation

The standard deviation in feet is $\frac{9.6}{12}=0.8$ feet.

Step5: Convert IQR

The IQR in feet is $\frac{5.5}{12}\approx0.46$ feet.

Answer:

The mean changes to approximately 3.42 feet, the median changes to 3.25 feet, the standard deviation changes to 0.8 feet, and the IQR changes to approximately 0.46 feet.