QUESTION IMAGE
Question
6 from unit 1, lesson 9 what effect does eliminating the highest value, 180, from the data set have on the mean and median? 25 50 50 60 70 85 85 90 90 180
Step1: Calculate the original mean
The formula for the mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$. Here $n = 10$, and $\sum_{i=1}^{10}x_{i}=25 + 50+50 + 60+70+85+85+90+90+180=785$. So the original mean $\bar{x}_1=\frac{785}{10}=78.5$.
Step2: Calculate the original median
Since $n = 10$ (an even - numbered data set), the median is the average of the $\frac{n}{2}$th and $(\frac{n}{2}+1)$th ordered values. The ordered data set is $25,50,50,60,70,85,85,90,90,180$. The $\frac{n}{2}=5$th value is $70$ and the $(\frac{n}{2}+1) = 6$th value is $85$. So the original median $M_1=\frac{70 + 85}{2}=77.5$.
Step3: Calculate the new mean after eliminating 180
Now $n = 9$, and $\sum_{i = 1}^{9}x_{i}=785-180 = 605$. So the new mean $\bar{x}_2=\frac{605}{9}\approx67.22$.
Step4: Calculate the new median after eliminating 180
Since $n = 9$ (an odd - numbered data set), the median is the $(\frac{n + 1}{2})$th ordered value. The ordered data set without 180 is $25,50,50,60,70,85,85,90,90$. The $(\frac{9+1}{2})=5$th value is $70$. So the new median $M_2 = 70$.
Step5: Analyze the effects
The mean decreases from $78.5$ to approximately $67.22$. The median decreases from $77.5$ to $70$.
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The mean and median both decrease.